Ik krijg steeds een parse error in regel 62. Maar ik zie de fout niet...
Zien jullie het ?
Zien jullie het ?
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| <?
mysql_connect("localhost","naam","password");
mysql_select_db("members");
if(!isset($cmd))
{
$result = mysql_query("select * from personeel order by id");
while($r=mysql_fetch_array($result))
{
$title=$r["username"];
$id=$r["id"];
echo "<a href='edit.php?cmd=edit&id=$id'>$title - Edit</a>";
echo "<br>";
}
}
?>
<?
if($_GET["cmd"]=="edit" || $_POST["cmd"]=="edit")
{
if (!isset($_POST["submit"]))
{
$id = $_GET["id"];
$sql = "SELECT * FROM personeel WHERE id=$id";
$result = mysql_query($sql);
$myrow = mysql_fetch_array($result);
?>
<form action="edit.php" method="post">
<input type=hidden name="id" value="<?php echo $myrow["id"] ?>">
Naam:<INPUT TYPE="TEXT" NAME="title" VALUE="<?php echo $myrow["username"] ?>" SIZE=30><br>
Password:<INPUT TYPE="TEXT" NAME="title" VALUE="<?php echo $myrow["password"] ?>" SIZE=30><br>
Strippen: <INPUT TYPE="TEXT" NAME="title" VALUE="<?php echo $myrow["stripen"] ?>" SIZE=30><br>
<input type="hidden" name="cmd" value="edit">
<input type="submit" name="submit" value="submit">
</form>
<? } ?>
<?
if ($_POST["$submit"])
{
$title = $_POST["username"];
$message = $_POST["password"];
$who = $_POST["strippen"];
$sql = "UPDATE personeel SET title='$username',message='$password',who='$strippen' WHERE id=$id";
$result = mysql_query($sql);
echo "Thank you! Information updated.";
}
?> |