Hallo,
Ik zal eerst even uitleggen wat ik graag wil:
Ik zou graag willen dat hij 6 random plaatjes uit een database trekt en dan gelijk uit de tabel users de gegevens van de gebruiker haalt, en ik kan nu van iedere gebruiker ook zijn homepage en email vermelden.
Ook het aantal plaatjes wat de user geupload heeft laat hij zien.
Nu werkt het wel goed, maar ik vraag mij of of dit zo goed is of dat er nog een betere manier is of snellere manier:
Bedankt alvast
Ik zal eerst even uitleggen wat ik graag wil:
Ik zou graag willen dat hij 6 random plaatjes uit een database trekt en dan gelijk uit de tabel users de gegevens van de gebruiker haalt, en ik kan nu van iedere gebruiker ook zijn homepage en email vermelden.
Ook het aantal plaatjes wat de user geupload heeft laat hij zien.
Nu werkt het wel goed, maar ik vraag mij of of dit zo goed is of dat er nog een betere manier is of snellere manier:
PHP:
1
| <? global $user, $dbi, $prefix; include 'admin/config.php'; mt_srand((double)microtime()*100000); $total = mysql_fetch_array(mysql_query("SELECT COUNT(p.pid) AS total FROM gallery_pictures" AS p LEFT JOIN gallery_categories" AS c ON c.gallid=p.gid WHERE c.visible>=1")); $total1 = mysql_fetch_array(mysql_query("SELECT COUNT(q.pid) AS total FROM gallery_pictures" AS q LEFT JOIN gallery_categories" AS d ON d.gallid=q.gid WHERE d.visible>=1")); $total2 = mysql_fetch_array(mysql_query("SELECT COUNT(r.pid) AS total FROM gallery_pictures" AS r LEFT JOIN gallery_categories" AS e ON e.gallid=r.gid WHERE e.visible>=1")); $total3 = mysql_fetch_array(mysql_query("SELECT COUNT(s.pid) AS total FROM gallery_pictures" AS s LEFT JOIN gallery_categories" AS f ON f.gallid=s.gid WHERE f.visible>=1")); $total4 = mysql_fetch_array(mysql_query("SELECT COUNT(t.pid) AS total FROM gallery_pictures" AS t LEFT JOIN gallery_categories" AS g ON g.gallid=t.gid WHERE g.visible>=1")); $total5 = mysql_fetch_array(mysql_query("SELECT COUNT(u.pid) AS total FROM gallery_pictures" AS u LEFT JOIN gallery_categories" AS h ON h.gallid=u.gid WHERE h.visible>=1")); $p = mt_rand(0,($total[total] - 1)); $q = mt_rand(0,($total1[total] - 1)); $r = mt_rand(0,($total2[total] - 1)); $s = mt_rand(0,($total3[total] - 1)); $t = mt_rand(0,($total4[total] - 1)); $u = mt_rand(0,($total5[total] - 1)); $pic = mysql_fetch_array(mysql_query("SELECT p.pid, p.submitter, p.img, p.name, p.description, c.galloc FROM gallery_pictures" AS p LEFT JOIN gallery_categories" AS c ON c.gallid=p.gid LIMIT $p,1")); $pic1 = mysql_fetch_array(mysql_query("SELECT q.pid, q.submitter, q.img, q.name, q.description, d.galloc FROM gallery_pictures" AS q LEFT JOIN gallery_categories" AS d ON d.gallid=q.gid LIMIT $q,2")); $pic2 = mysql_fetch_array(mysql_query("SELECT r.pid, r.submitter, r.img, r.name, r.description, e.galloc FROM gallery_pictures" AS r LEFT JOIN gallery_categories" AS e ON e.gallid=r.gid LIMIT $r,3")); $pic3 = mysql_fetch_array(mysql_query("SELECT s.pid, s.submitter, s.img, s.name, s.description, f.galloc FROM gallery_pictures" AS s LEFT JOIN gallery_categories" AS f ON f.gallid=s.gid LIMIT $s,4")); $pic4 = mysql_fetch_array(mysql_query("SELECT t.pid, t.submitter, t.img, t.name, t.description, g.galloc FROM gallery_pictures" AS t LEFT JOIN gallery_categories" AS g ON g.gallid=t.gid LIMIT $t,5")); $pic5 = mysql_fetch_array(mysql_query("SELECT u.pid, u.submitter, u.img, u.name, u.description, h.galloc FROM gallery_pictures" AS u LEFT JOIN gallery_categories" AS h ON h.gallid=u.gid LIMIT $u,6")); $usr = mysql_fetch_array(mysql_query("SELECT uname, email, url FROM users" WHERE uname = '$pic[submitter]'")); $usr1 = mysql_fetch_array(mysql_query("SELECT uname, email, url FROM users" WHERE uname = '$pic1[submitter]'")); $usr2 = mysql_fetch_array(mysql_query("SELECT uname, email, url FROM users" WHERE uname = '$pic2[submitter]'")); $usr3 = mysql_fetch_array(mysql_query("SELECT uname, email, url FROM users" WHERE uname = '$pic3[submitter]'")); $usr4 = mysql_fetch_array(mysql_query("SELECT uname, email, url FROM users" WHERE uname = '$pic4[submitter]'")); $usr5 = mysql_fetch_array(mysql_query("SELECT uname, email, url FROM users" WHERE uname = '$pic5[submitter]'")); $pic[description] = htmlentities($pic[description]); $pic1[description] = htmlentities($pic1[description]); $pic2[description] = htmlentities($pic2[description]); $pic3[description] = htmlentities($pic3[description]); $pic4[description] = htmlentities($pic4[description]); $pic5[description] = htmlentities($pic5[description]); $pnum = sql_num_rows(sql_query("select * from gallery_pictures where submitter = '$pic[submitter]'", $dbi)); $pnum1 = sql_num_rows(sql_query("select * from gallery_pictures where submitter = '$pic1[submitter]'", $dbi)); $pnum2 = sql_num_rows(sql_query("select * from gallery_pictures where submitter = '$pic2[submitter]'", $dbi)); $pnum3 = sql_num_rows(sql_query("select * from gallery_pictures where submitter = '$pic3[submitter]'", $dbi)); $pnum4 = sql_num_rows(sql_query("select * from gallery_pictures where submitter = '$pic4[submitter]'", $dbi)); $pnum5 = sql_num_rows(sql_query("select * from gallery_pictures where submitter = '$pic5[submitter]'", $dbi)); ?> |
Bedankt alvast