Bash -

[xirixiz]

Hey,

I'm trying to create a bash script to do the following;

example source files:
- a_b_c_qwer_e_123.xml
- a_b_c_rewq_e_abc.xml
- a_b_c_tyui_e_cba.xml
- a_b_c_iuyt_e_321.xml
- a_b_c_qazws_e_000.xml
- a_b_c_swzaq_e_333.xml

What i would like to do is extract the first part of a filename.

For example "a_b_c_qwer_e_123.xml" is the filename, what I need to extract is this part: "a_b_c_qwer_e" without the source filnames being renamed.

Then the following needs to be done. Based on the first part of the file, in this case "a_b_c_qwer_e", the file has to be copied to the directory "/a_b_c_qwer_e". So actually it's a (partly)filename based copy.

What I've created so far is the following...which sux due to I`m creating a lot of variables this way.
I searched on google but couldn't find a good result. Hope someone can help me out! Tx!


#!/bin/bash

QUEUE_01="a_b_c_qwer_e"
QUEUE_02="a_b_c_rewq_e"
QUEUE_03="a_b_c_tyui_e"
QUEUE_04="a_b_c_iuyt_e"
QUEUE_05="a_b_c_qazws_e"
QUEUE_06="a_b_c_swzaq_e"

ls -1 | while read file
do
cp $file $(echo $file | cut -f1 -d"_" ).$(echo $file | cut -f2 -d".")
done

[Emmeau]

dit is typisch iets voor sed

regexp bouwen die doet wat je wilt, en de bestandsnamen er doorheen halen.

Succes
En je post mag/moet gewoon in het nederlands

[ Voor 21% gewijzigd door Emmeau op 23-11-2009 15:42 ]

[RobIII]

We speaken Dutch hier op tweakers.net
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